4(m-3)+20=4(m+2)

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Solution for 4(m-3)+20=4(m+2) equation:



4(m-3)+20=4(m+2)
We move all terms to the left:
4(m-3)+20-(4(m+2))=0
We multiply parentheses
4m-(4(m+2))-12+20=0
We calculate terms in parentheses: -(4(m+2)), so:
4(m+2)
We multiply parentheses
4m+8
Back to the equation:
-(4m+8)
We add all the numbers together, and all the variables
4m-(4m+8)+8=0
We get rid of parentheses
4m-4m-8+8=0
We add all the numbers together, and all the variables
=0
m=0/1
m=0

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