4(m-3)+19=8(2m+3)=7

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Solution for 4(m-3)+19=8(2m+3)=7 equation: 



4(m-3)+19=8(2m+3)=7

We move all terms to the left:

4(m-3)+19-(8(2m+3))=0

We multiply parentheses

4m-(8(2m+3))-12+19=0



We calculate terms in parentheses: -(8(2m+3)), so:

8(2m+3)

We multiply parentheses

16m+24

Back to the equation:

-(16m+24)



We add all the numbers together, and all the variables

4m-(16m+24)+7=0

We get rid of parentheses

4m-16m-24+7=0

We add all the numbers together, and all the variables

-12m-17=0

We move all terms containing m to the left, all other terms to the right

-12m=17

m=17/-12

m=-1+5/12

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