4(m-3)+19=8(2m+3)+7

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Solution for 4(m-3)+19=8(2m+3)+7 equation: 



4(m-3)+19=8(2m+3)+7

We move all terms to the left:

4(m-3)+19-(8(2m+3)+7)=0

We multiply parentheses

4m-(8(2m+3)+7)-12+19=0



We calculate terms in parentheses: -(8(2m+3)+7), so:

8(2m+3)+7

We multiply parentheses

16m+24+7

We add all the numbers together, and all the variables

16m+31

Back to the equation:

-(16m+31)



We add all the numbers together, and all the variables

4m-(16m+31)+7=0

We get rid of parentheses

4m-16m-31+7=0

We add all the numbers together, and all the variables

-12m-24=0

We move all terms containing m to the left, all other terms to the right

-12m=24

m=24/-12

m=-2

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