4(m-1)=8(m-1)+12

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Solution for 4(m-1)=8(m-1)+12 equation: 



4(m-1)=8(m-1)+12

We move all terms to the left:

4(m-1)-(8(m-1)+12)=0

We multiply parentheses

4m-(8(m-1)+12)-4=0



We calculate terms in parentheses: -(8(m-1)+12), so:

8(m-1)+12

We multiply parentheses

8m-8+12

We add all the numbers together, and all the variables

8m+4

Back to the equation:

-(8m+4)



We get rid of parentheses

4m-8m-4-4=0

We add all the numbers together, and all the variables

-4m-8=0

We move all terms containing m to the left, all other terms to the right

-4m=8

m=8/-4

m=-2

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