4(m+2)-7=3(m-5)+4

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Solution for 4(m+2)-7=3(m-5)+4 equation: 



4(m+2)-7=3(m-5)+4

We move all terms to the left:

4(m+2)-7-(3(m-5)+4)=0

We multiply parentheses

4m-(3(m-5)+4)+8-7=0



We calculate terms in parentheses: -(3(m-5)+4), so:

3(m-5)+4

We multiply parentheses

3m-15+4

We add all the numbers together, and all the variables

3m-11

Back to the equation:

-(3m-11)



We add all the numbers together, and all the variables

4m-(3m-11)+1=0

We get rid of parentheses

4m-3m+11+1=0

We add all the numbers together, and all the variables

m+12=0

We move all terms containing m to the left, all other terms to the right

m=-12

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