4(m+2)-3=4m+5

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Solution for 4(m+2)-3=4m+5 equation: 


Simplifying
4(m + 2) + -3 = 4m + 5

Reorder the terms:
4(2 + m) + -3 = 4m + 5
(2 * 4 + m * 4) + -3 = 4m + 5
(8 + 4m) + -3 = 4m + 5

Reorder the terms:
8 + -3 + 4m = 4m + 5

Combine like terms: 8 + -3 = 5
5 + 4m = 4m + 5

Reorder the terms:
5 + 4m = 5 + 4m

Add '-5' to each side of the equation.
5 + -5 + 4m = 5 + -5 + 4m

Combine like terms: 5 + -5 = 0
0 + 4m = 5 + -5 + 4m
4m = 5 + -5 + 4m

Combine like terms: 5 + -5 = 0
4m = 0 + 4m
4m = 4m

Add '-4m' to each side of the equation.
4m + -4m = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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