4(m+1/2)=(2(4m))-6

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Solution for 4(m+1/2)=(2(4m))-6 equation: 



4(m+1/2)=(2(4m))-6

We move all terms to the left:

4(m+1/2)-((2(4m))-6)=0

determiningTheFunctionDomain
4(m+1/2)-(24m-6)=0

We add all the numbers together, and all the variables

4(+m+1/2)-(24m-6)=0

We multiply parentheses

4m-(24m-6)+1/2*4=0

We get rid of parentheses

4m-24m+6+1/2*4=0

We multiply all the terms by the denominator


4m*2*4-24m*2*4+1+6*2*4=0

We add all the numbers together, and all the variables

4m*2*4-24m*2*4+49=0

Wy multiply elements

32m*4-192m*4+49=0

Wy multiply elements

128m-768m+49=0

We add all the numbers together, and all the variables

-640m+49=0

We move all terms containing m to the left, all other terms to the right

-640m=-49

m=-49/-640

m=49/640

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