4(k-5)=28

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Solution for 4(k-5)=28 equation: 



4(k-5)=28

We move all terms to the left:

4(k-5)-(28)=0

We multiply parentheses

4k-20-28=0

We add all the numbers together, and all the variables

4k-48=0

We move all terms containing k to the left, all other terms to the right

4k=48

k=48/4

k=12

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