4(k-5)=2(2k-9)-2

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Solution for 4(k-5)=2(2k-9)-2 equation:


Simplifying
4(k + -5) = 2(2k + -9) + -2

Reorder the terms:
4(-5 + k) = 2(2k + -9) + -2
(-5 * 4 + k * 4) = 2(2k + -9) + -2
(-20 + 4k) = 2(2k + -9) + -2

Reorder the terms:
-20 + 4k = 2(-9 + 2k) + -2
-20 + 4k = (-9 * 2 + 2k * 2) + -2
-20 + 4k = (-18 + 4k) + -2

Reorder the terms:
-20 + 4k = -18 + -2 + 4k

Combine like terms: -18 + -2 = -20
-20 + 4k = -20 + 4k

Add '20' to each side of the equation.
-20 + 20 + 4k = -20 + 20 + 4k

Combine like terms: -20 + 20 = 0
0 + 4k = -20 + 20 + 4k
4k = -20 + 20 + 4k

Combine like terms: -20 + 20 = 0
4k = 0 + 4k
4k = 4k

Add '-4k' to each side of the equation.
4k + -4k = 4k + -4k

Combine like terms: 4k + -4k = 0
0 = 4k + -4k

Combine like terms: 4k + -4k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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