4(k-3)=2k+5

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Solution for 4(k-3)=2k+5 equation: 



4(k-3)=2k+5

We move all terms to the left:

4(k-3)-(2k+5)=0

We multiply parentheses

4k-(2k+5)-12=0

We get rid of parentheses

4k-2k-5-12=0

We add all the numbers together, and all the variables

2k-17=0

We move all terms containing k to the left, all other terms to the right

2k=17

k=17/2

k=8+1/2

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