4(k-3)=2(k+1)-6

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Solution for 4(k-3)=2(k+1)-6 equation:


Simplifying
4(k + -3) = 2(k + 1) + -6

Reorder the terms:
4(-3 + k) = 2(k + 1) + -6
(-3 * 4 + k * 4) = 2(k + 1) + -6
(-12 + 4k) = 2(k + 1) + -6

Reorder the terms:
-12 + 4k = 2(1 + k) + -6
-12 + 4k = (1 * 2 + k * 2) + -6
-12 + 4k = (2 + 2k) + -6

Reorder the terms:
-12 + 4k = 2 + -6 + 2k

Combine like terms: 2 + -6 = -4
-12 + 4k = -4 + 2k

Solving
-12 + 4k = -4 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-12 + 4k + -2k = -4 + 2k + -2k

Combine like terms: 4k + -2k = 2k
-12 + 2k = -4 + 2k + -2k

Combine like terms: 2k + -2k = 0
-12 + 2k = -4 + 0
-12 + 2k = -4

Add '12' to each side of the equation.
-12 + 12 + 2k = -4 + 12

Combine like terms: -12 + 12 = 0
0 + 2k = -4 + 12
2k = -4 + 12

Combine like terms: -4 + 12 = 8
2k = 8

Divide each side by '2'.
k = 4

Simplifying
k = 4

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