4(k+3)=3(k-2)

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Solution for 4(k+3)=3(k-2) equation:


Simplifying
4(k + 3) = 3(k + -2)

Reorder the terms:
4(3 + k) = 3(k + -2)
(3 * 4 + k * 4) = 3(k + -2)
(12 + 4k) = 3(k + -2)

Reorder the terms:
12 + 4k = 3(-2 + k)
12 + 4k = (-2 * 3 + k * 3)
12 + 4k = (-6 + 3k)

Solving
12 + 4k = -6 + 3k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-3k' to each side of the equation.
12 + 4k + -3k = -6 + 3k + -3k

Combine like terms: 4k + -3k = 1k
12 + 1k = -6 + 3k + -3k

Combine like terms: 3k + -3k = 0
12 + 1k = -6 + 0
12 + 1k = -6

Add '-12' to each side of the equation.
12 + -12 + 1k = -6 + -12

Combine like terms: 12 + -12 = 0
0 + 1k = -6 + -12
1k = -6 + -12

Combine like terms: -6 + -12 = -18
1k = -18

Divide each side by '1'.
k = -18

Simplifying
k = -18

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