4(k+3)+2(k+1)=20

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Solution for 4(k+3)+2(k+1)=20 equation: 



4(k+3)+2(k+1)=20

We move all terms to the left:

4(k+3)+2(k+1)-(20)=0

We multiply parentheses

4k+2k+12+2-20=0

We add all the numbers together, and all the variables

6k-6=0

We move all terms containing k to the left, all other terms to the right

6k=6

k=6/6

k=1

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