4(k+2)=3(k-1)

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Solution for 4(k+2)=3(k-1) equation: 


Simplifying
4(k + 2) = 3(k + -1)

Reorder the terms:
4(2 + k) = 3(k + -1)
(2 * 4 + k * 4) = 3(k + -1)
(8 + 4k) = 3(k + -1)

Reorder the terms:
8 + 4k = 3(-1 + k)
8 + 4k = (-1 * 3 + k * 3)
8 + 4k = (-3 + 3k)

Solving
8 + 4k = -3 + 3k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-3k' to each side of the equation.
8 + 4k + -3k = -3 + 3k + -3k

Combine like terms: 4k + -3k = 1k
8 + 1k = -3 + 3k + -3k

Combine like terms: 3k + -3k = 0
8 + 1k = -3 + 0
8 + 1k = -3

Add '-8' to each side of the equation.
8 + -8 + 1k = -3 + -8

Combine like terms: 8 + -8 = 0
0 + 1k = -3 + -8
1k = -3 + -8

Combine like terms: -3 + -8 = -11
1k = -11

Divide each side by '1'.
k = -11

Simplifying
k = -11

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