4(k+2)=3(k+2)+k

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Solution for 4(k+2)=3(k+2)+k equation: 



4(k+2)=3(k+2)+k

We move all terms to the left:

4(k+2)-(3(k+2)+k)=0

We multiply parentheses

4k-(3(k+2)+k)+8=0



We calculate terms in parentheses: -(3(k+2)+k), so:

3(k+2)+k

We add all the numbers together, and all the variables

k+3(k+2)

We multiply parentheses

k+3k+6

We add all the numbers together, and all the variables

4k+6

Back to the equation:

-(4k+6)



We get rid of parentheses

4k-4k-6+8=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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