4(k+2)=-3(k-4)

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Solution for 4(k+2)=-3(k-4) equation: 



4(k+2)=-3(k-4)

We move all terms to the left:

4(k+2)-(-3(k-4))=0

We multiply parentheses

4k-(-3(k-4))+8=0



We calculate terms in parentheses: -(-3(k-4)), so:

-3(k-4)

We multiply parentheses

-3k+12

Back to the equation:

-(-3k+12)



We get rid of parentheses

4k+3k-12+8=0

We add all the numbers together, and all the variables

7k-4=0

We move all terms containing k to the left, all other terms to the right

7k=4

k=4/7

k=4/7

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