4(j-7)=128

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Solution for 4(j-7)=128 equation: 



4(j-7)=128

We move all terms to the left:

4(j-7)-(128)=0

We multiply parentheses

4j-28-128=0

We add all the numbers together, and all the variables

4j-156=0

We move all terms containing j to the left, all other terms to the right

4j=156

j=156/4

j=39

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