4(j+4)+3j=3(28+j

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Solution for 4(j+4)+3j=3(28+j equation: 



4(j+4)+3j=3(28+j

We move all terms to the left:

4(j+4)+3j-(3(28+j)=0

We add all the numbers together, and all the variables

4(j+4)+3j-(3(j+28)=0

We add all the numbers together, and all the variables

3j+4(j+4)-(3(j+28)=0

We multiply parentheses

3j+4j-(3(j+28)+16=0

We add all the numbers together, and all the variables

7j-(3(j+28)+16=0

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