4(j+28)=-80

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Solution for 4(j+28)=-80 equation: 



4(j+28)=-80

We move all terms to the left:

4(j+28)-(-80)=0

We add all the numbers together, and all the variables

4(j+28)+80=0

We multiply parentheses

4j+112+80=0

We add all the numbers together, and all the variables

4j+192=0

We move all terms containing j to the left, all other terms to the right

4j=-192

j=-192/4

j=-48

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