4(j+2)+3(j+1)=-3

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Solution for 4(j+2)+3(j+1)=-3 equation: 


Simplifying
4(j + 2) + 3(j + 1) = -3

Reorder the terms:
4(2 + j) + 3(j + 1) = -3
(2 * 4 + j * 4) + 3(j + 1) = -3
(8 + 4j) + 3(j + 1) = -3

Reorder the terms:
8 + 4j + 3(1 + j) = -3
8 + 4j + (1 * 3 + j * 3) = -3
8 + 4j + (3 + 3j) = -3

Reorder the terms:
8 + 3 + 4j + 3j = -3

Combine like terms: 8 + 3 = 11
11 + 4j + 3j = -3

Combine like terms: 4j + 3j = 7j
11 + 7j = -3

Solving
11 + 7j = -3

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 7j = -3 + -11

Combine like terms: 11 + -11 = 0
0 + 7j = -3 + -11
7j = -3 + -11

Combine like terms: -3 + -11 = -14
7j = -14

Divide each side by '7'.
j = -2

Simplifying
j = -2

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