4(i-1)=2i+22

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Solution for 4(i-1)=2i+22 equation: 



4(i-1)=2i+22

We move all terms to the left:

4(i-1)-(2i+22)=0

We multiply parentheses

4i-(2i+22)-4=0

We get rid of parentheses

4i-2i-22-4=0

We add all the numbers together, and all the variables

2i-26=0

We move all terms containing i to the left, all other terms to the right

2i=26

i=26/2

i=13

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