4(h+i)+(2h+3i)=

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Solution for 4(h+i)+(2h+3i)= equation:


Simplifying
4(h + i) + (2h + 3i) = 0
(h * 4 + i * 4) + (2h + 3i) = 0
(4h + 4i) + (2h + 3i) = 0

Remove parenthesis around (2h + 3i)
4h + 4i + 2h + 3i = 0

Reorder the terms:
4h + 2h + 4i + 3i = 0

Combine like terms: 4h + 2h = 6h
6h + 4i + 3i = 0

Combine like terms: 4i + 3i = 7i
6h + 7i = 0

Solving
6h + 7i = 0

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-7i' to each side of the equation.
6h + 7i + -7i = 0 + -7i

Combine like terms: 7i + -7i = 0
6h + 0 = 0 + -7i
6h = 0 + -7i
Remove the zero:
6h = -7i

Divide each side by '6'.
h = -1.166666667i

Simplifying
h = -1.166666667i

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