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4(f+2)=2(2f+4)
We move all terms to the left:
4(f+2)-(2(2f+4))=0
We multiply parentheses
4f-(2(2f+4))+8=0
We calculate terms in parentheses: -(2(2f+4)), so:We get rid of parentheses
2(2f+4)
We multiply parentheses
4f+8
Back to the equation:
-(4f+8)
4f-4f-8+8=0
We add all the numbers together, and all the variables
=0
f=0/1
f=0
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