4(f+2)-3=2(f-1)-9

Solution for 4(f+2)-3=2(f-1)-9 equation:

4(f+2)-3=2(f-1)-9

We move all terms to the left:

4(f+2)-3-(2(f-1)-9)=0

We multiply parentheses

4f-(2(f-1)-9)+8-3=0


We calculate terms in parentheses: -(2(f-1)-9), so:

2(f-1)-9

We multiply parentheses

2f-2-9

We add all the numbers together, and all the variables

2f-11

Back to the equation:

-(2f-11)


We add all the numbers together, and all the variables

4f-(2f-11)+5=0

We get rid of parentheses

4f-2f+11+5=0

We add all the numbers together, and all the variables

2f+16=0

We move all terms containing f to the left, all other terms to the right

2f=-16

f=-16/2

f=-8