4(d-7)+2d=32

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Solution for 4(d-7)+2d=32 equation: 



4(d-7)+2d=32

We move all terms to the left:

4(d-7)+2d-(32)=0

We add all the numbers together, and all the variables

2d+4(d-7)-32=0

We multiply parentheses

2d+4d-28-32=0

We add all the numbers together, and all the variables

6d-60=0

We move all terms containing d to the left, all other terms to the right

6d=60

d=60/6

d=10

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