4(d-5)-6=2(8-d)-4

Solution for 4(d-5)-6=2(8-d)-4 equation:

4(d-5)-6=2(8-d)-4

We move all terms to the left:

4(d-5)-6-(2(8-d)-4)=0

We add all the numbers together, and all the variables

4(d-5)-(2(-1d+8)-4)-6=0

We multiply parentheses

4d-(2(-1d+8)-4)-20-6=0


We calculate terms in parentheses: -(2(-1d+8)-4), so:

2(-1d+8)-4

We multiply parentheses

-2d+16-4

We add all the numbers together, and all the variables

-2d+12

Back to the equation:

-(-2d+12)


We add all the numbers together, and all the variables

4d-(-2d+12)-26=0

We get rid of parentheses

4d+2d-12-26=0

We add all the numbers together, and all the variables

6d-38=0

We move all terms containing d to the left, all other terms to the right

6d=38

d=38/6

d=6+1/3