4(d-3)+5=3(d+2)-7

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Solution for 4(d-3)+5=3(d+2)-7 equation: 



4(d-3)+5=3(d+2)-7

We move all terms to the left:

4(d-3)+5-(3(d+2)-7)=0

We multiply parentheses

4d-(3(d+2)-7)-12+5=0



We calculate terms in parentheses: -(3(d+2)-7), so:

3(d+2)-7

We multiply parentheses

3d+6-7

We add all the numbers together, and all the variables

3d-1

Back to the equation:

-(3d-1)



We add all the numbers together, and all the variables

4d-(3d-1)-7=0

We get rid of parentheses

4d-3d+1-7=0

We add all the numbers together, and all the variables

d-6=0

We move all terms containing d to the left, all other terms to the right

d=6

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