4(d-3)+19=8(2d+3)+7

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Solution for 4(d-3)+19=8(2d+3)+7 equation: 



4(d-3)+19=8(2d+3)+7

We move all terms to the left:

4(d-3)+19-(8(2d+3)+7)=0

We multiply parentheses

4d-(8(2d+3)+7)-12+19=0



We calculate terms in parentheses: -(8(2d+3)+7), so:

8(2d+3)+7

We multiply parentheses

16d+24+7

We add all the numbers together, and all the variables

16d+31

Back to the equation:

-(16d+31)



We add all the numbers together, and all the variables

4d-(16d+31)+7=0

We get rid of parentheses

4d-16d-31+7=0

We add all the numbers together, and all the variables

-12d-24=0

We move all terms containing d to the left, all other terms to the right

-12d=24

d=24/-12

d=-2

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