4(d+5)-2(d+3)=12

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Solution for 4(d+5)-2(d+3)=12 equation:


Simplifying
4(d + 5) + -2(d + 3) = 12

Reorder the terms:
4(5 + d) + -2(d + 3) = 12
(5 * 4 + d * 4) + -2(d + 3) = 12
(20 + 4d) + -2(d + 3) = 12

Reorder the terms:
20 + 4d + -2(3 + d) = 12
20 + 4d + (3 * -2 + d * -2) = 12
20 + 4d + (-6 + -2d) = 12

Reorder the terms:
20 + -6 + 4d + -2d = 12

Combine like terms: 20 + -6 = 14
14 + 4d + -2d = 12

Combine like terms: 4d + -2d = 2d
14 + 2d = 12

Solving
14 + 2d = 12

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 2d = 12 + -14

Combine like terms: 14 + -14 = 0
0 + 2d = 12 + -14
2d = 12 + -14

Combine like terms: 12 + -14 = -2
2d = -2

Divide each side by '2'.
d = -1

Simplifying
d = -1

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