4(d+3)=4d+12

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Solution for 4(d+3)=4d+12 equation: 


Simplifying
4(d + 3) = 4d + 12

Reorder the terms:
4(3 + d) = 4d + 12
(3 * 4 + d * 4) = 4d + 12
(12 + 4d) = 4d + 12

Reorder the terms:
12 + 4d = 12 + 4d

Add '-12' to each side of the equation.
12 + -12 + 4d = 12 + -12 + 4d

Combine like terms: 12 + -12 = 0
0 + 4d = 12 + -12 + 4d
4d = 12 + -12 + 4d

Combine like terms: 12 + -12 = 0
4d = 0 + 4d
4d = 4d

Add '-4d' to each side of the equation.
4d + -4d = 4d + -4d

Combine like terms: 4d + -4d = 0
0 = 4d + -4d

Combine like terms: 4d + -4d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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