4(d+2)-d=3(2-d)

Solution for 4(d+2)-d=3(2-d) equation:

4(d+2)-d=3(2-d)

We move all terms to the left:

4(d+2)-d-(3(2-d))=0

We add all the numbers together, and all the variables

4(d+2)-d-(3(-1d+2))=0

We add all the numbers together, and all the variables

-1d+4(d+2)-(3(-1d+2))=0

We multiply parentheses

-1d+4d-(3(-1d+2))+8=0


We calculate terms in parentheses: -(3(-1d+2)), so:

3(-1d+2)

We multiply parentheses

-3d+6

Back to the equation:

-(-3d+6)


We add all the numbers together, and all the variables

3d-(-3d+6)+8=0

We get rid of parentheses

3d+3d-6+8=0

We add all the numbers together, and all the variables

6d+2=0

We move all terms containing d to the left, all other terms to the right

6d=-2

d=-2/6

d=-1/3