4(d+1)=6(d-3)

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Solution for 4(d+1)=6(d-3) equation:


Simplifying
4(d + 1) = 6(d + -3)

Reorder the terms:
4(1 + d) = 6(d + -3)
(1 * 4 + d * 4) = 6(d + -3)
(4 + 4d) = 6(d + -3)

Reorder the terms:
4 + 4d = 6(-3 + d)
4 + 4d = (-3 * 6 + d * 6)
4 + 4d = (-18 + 6d)

Solving
4 + 4d = -18 + 6d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-6d' to each side of the equation.
4 + 4d + -6d = -18 + 6d + -6d

Combine like terms: 4d + -6d = -2d
4 + -2d = -18 + 6d + -6d

Combine like terms: 6d + -6d = 0
4 + -2d = -18 + 0
4 + -2d = -18

Add '-4' to each side of the equation.
4 + -4 + -2d = -18 + -4

Combine like terms: 4 + -4 = 0
0 + -2d = -18 + -4
-2d = -18 + -4

Combine like terms: -18 + -4 = -22
-2d = -22

Divide each side by '-2'.
d = 11

Simplifying
d = 11

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