4(c-6)=3c+15+c

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Solution for 4(c-6)=3c+15+c equation: 



4(c-6)=3c+15+c

We move all terms to the left:

4(c-6)-(3c+15+c)=0

We add all the numbers together, and all the variables

4(c-6)-(4c+15)=0

We multiply parentheses

4c-(4c+15)-24=0

We get rid of parentheses

4c-4c-15-24=0

We add all the numbers together, and all the variables

-39!=0

There is no solution for this equation

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