4(c-6)=2+6(7-6c)

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Solution for 4(c-6)=2+6(7-6c) equation: 



4(c-6)=2+6(7-6c)

We move all terms to the left:

4(c-6)-(2+6(7-6c))=0

We add all the numbers together, and all the variables

4(c-6)-(2+6(-6c+7))=0

We multiply parentheses

4c-(2+6(-6c+7))-24=0



We calculate terms in parentheses: -(2+6(-6c+7)), so:

2+6(-6c+7)

determiningTheFunctionDomain
6(-6c+7)+2

We multiply parentheses

-36c+42+2

We add all the numbers together, and all the variables

-36c+44

Back to the equation:

-(-36c+44)



We get rid of parentheses

4c+36c-44-24=0

We add all the numbers together, and all the variables

40c-68=0

We move all terms containing c to the left, all other terms to the right

40c=68

c=68/40

c=1+7/10

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