4(c-4)+4=3+c-15

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Solution for 4(c-4)+4=3+c-15 equation: 


Simplifying
4(c + -4) + 4 = 3 + c + -15

Reorder the terms:
4(-4 + c) + 4 = 3 + c + -15
(-4 * 4 + c * 4) + 4 = 3 + c + -15
(-16 + 4c) + 4 = 3 + c + -15

Reorder the terms:
-16 + 4 + 4c = 3 + c + -15

Combine like terms: -16 + 4 = -12
-12 + 4c = 3 + c + -15

Reorder the terms:
-12 + 4c = 3 + -15 + c

Combine like terms: 3 + -15 = -12
-12 + 4c = -12 + c

Add '12' to each side of the equation.
-12 + 12 + 4c = -12 + 12 + c

Combine like terms: -12 + 12 = 0
0 + 4c = -12 + 12 + c
4c = -12 + 12 + c

Combine like terms: -12 + 12 = 0
4c = 0 + c
4c = c

Solving
4c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
4c + -1c = c + -1c

Combine like terms: 4c + -1c = 3c
3c = c + -1c

Combine like terms: c + -1c = 0
3c = 0

Divide each side by '3'.
c = 0

Simplifying
c = 0

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