4(c-3)-3(2c+1)=7c+3

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Solution for 4(c-3)-3(2c+1)=7c+3 equation:


Simplifying
4(c + -3) + -3(2c + 1) = 7c + 3

Reorder the terms:
4(-3 + c) + -3(2c + 1) = 7c + 3
(-3 * 4 + c * 4) + -3(2c + 1) = 7c + 3
(-12 + 4c) + -3(2c + 1) = 7c + 3

Reorder the terms:
-12 + 4c + -3(1 + 2c) = 7c + 3
-12 + 4c + (1 * -3 + 2c * -3) = 7c + 3
-12 + 4c + (-3 + -6c) = 7c + 3

Reorder the terms:
-12 + -3 + 4c + -6c = 7c + 3

Combine like terms: -12 + -3 = -15
-15 + 4c + -6c = 7c + 3

Combine like terms: 4c + -6c = -2c
-15 + -2c = 7c + 3

Reorder the terms:
-15 + -2c = 3 + 7c

Solving
-15 + -2c = 3 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
-15 + -2c + -7c = 3 + 7c + -7c

Combine like terms: -2c + -7c = -9c
-15 + -9c = 3 + 7c + -7c

Combine like terms: 7c + -7c = 0
-15 + -9c = 3 + 0
-15 + -9c = 3

Add '15' to each side of the equation.
-15 + 15 + -9c = 3 + 15

Combine like terms: -15 + 15 = 0
0 + -9c = 3 + 15
-9c = 3 + 15

Combine like terms: 3 + 15 = 18
-9c = 18

Divide each side by '-9'.
c = -2

Simplifying
c = -2

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