4(c-15)+6=18

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Solution for 4(c-15)+6=18 equation: 



4(c-15)+6=18

We move all terms to the left:

4(c-15)+6-(18)=0

We add all the numbers together, and all the variables

4(c-15)-12=0

We multiply parentheses

4c-60-12=0

We add all the numbers together, and all the variables

4c-72=0

We move all terms containing c to the left, all other terms to the right

4c=72

c=72/4

c=18

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