4(c-1)=6(c+2)+2c

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Solution for 4(c-1)=6(c+2)+2c equation:


Simplifying
4(c + -1) = 6(c + 2) + 2c

Reorder the terms:
4(-1 + c) = 6(c + 2) + 2c
(-1 * 4 + c * 4) = 6(c + 2) + 2c
(-4 + 4c) = 6(c + 2) + 2c

Reorder the terms:
-4 + 4c = 6(2 + c) + 2c
-4 + 4c = (2 * 6 + c * 6) + 2c
-4 + 4c = (12 + 6c) + 2c

Combine like terms: 6c + 2c = 8c
-4 + 4c = 12 + 8c

Solving
-4 + 4c = 12 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
-4 + 4c + -8c = 12 + 8c + -8c

Combine like terms: 4c + -8c = -4c
-4 + -4c = 12 + 8c + -8c

Combine like terms: 8c + -8c = 0
-4 + -4c = 12 + 0
-4 + -4c = 12

Add '4' to each side of the equation.
-4 + 4 + -4c = 12 + 4

Combine like terms: -4 + 4 = 0
0 + -4c = 12 + 4
-4c = 12 + 4

Combine like terms: 12 + 4 = 16
-4c = 16

Divide each side by '-4'.
c = -4

Simplifying
c = -4

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