4(c+5)=32

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Solution for 4(c+5)=32 equation: 



4(c+5)=32

We move all terms to the left:

4(c+5)-(32)=0

We multiply parentheses

4c+20-32=0

We add all the numbers together, and all the variables

4c-12=0

We move all terms containing c to the left, all other terms to the right

4c=12

c=12/4

c=3

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