4(c+3c)=2

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Solution for 4(c+3c)=2 equation: 



4(c+3c)=2

We move all terms to the left:

4(c+3c)-(2)=0

We add all the numbers together, and all the variables

4(+4c)-2=0

We multiply parentheses

16c-2=0

We move all terms containing c to the left, all other terms to the right

16c=2

c=2/16

c=1/8

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