4(c+3)=3(c+12)

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Solution for 4(c+3)=3(c+12) equation: 



4(c+3)=3(c+12)

We move all terms to the left:

4(c+3)-(3(c+12))=0

We multiply parentheses

4c-(3(c+12))+12=0



We calculate terms in parentheses: -(3(c+12)), so:

3(c+12)

We multiply parentheses

3c+36

Back to the equation:

-(3c+36)



We get rid of parentheses

4c-3c-36+12=0

We add all the numbers together, and all the variables

c-24=0

We move all terms containing c to the left, all other terms to the right

c=24

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