4(c+3)=2(9c-.5)

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Solution for 4(c+3)=2(9c-.5) equation:


Simplifying
4(c + 3) = 2(9c + -0.5)

Reorder the terms:
4(3 + c) = 2(9c + -0.5)
(3 * 4 + c * 4) = 2(9c + -0.5)
(12 + 4c) = 2(9c + -0.5)

Reorder the terms:
12 + 4c = 2(-0.5 + 9c)
12 + 4c = (-0.5 * 2 + 9c * 2)
12 + 4c = (-1 + 18c)

Solving
12 + 4c = -1 + 18c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-18c' to each side of the equation.
12 + 4c + -18c = -1 + 18c + -18c

Combine like terms: 4c + -18c = -14c
12 + -14c = -1 + 18c + -18c

Combine like terms: 18c + -18c = 0
12 + -14c = -1 + 0
12 + -14c = -1

Add '-12' to each side of the equation.
12 + -12 + -14c = -1 + -12

Combine like terms: 12 + -12 = 0
0 + -14c = -1 + -12
-14c = -1 + -12

Combine like terms: -1 + -12 = -13
-14c = -13

Divide each side by '-14'.
c = 0.9285714286

Simplifying
c = 0.9285714286

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