4(c+2)=7c+4-3c+4

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Solution for 4(c+2)=7c+4-3c+4 equation:


Simplifying
4(c + 2) = 7c + 4 + -3c + 4

Reorder the terms:
4(2 + c) = 7c + 4 + -3c + 4
(2 * 4 + c * 4) = 7c + 4 + -3c + 4
(8 + 4c) = 7c + 4 + -3c + 4

Reorder the terms:
8 + 4c = 4 + 4 + 7c + -3c

Combine like terms: 4 + 4 = 8
8 + 4c = 8 + 7c + -3c

Combine like terms: 7c + -3c = 4c
8 + 4c = 8 + 4c

Add '-8' to each side of the equation.
8 + -8 + 4c = 8 + -8 + 4c

Combine like terms: 8 + -8 = 0
0 + 4c = 8 + -8 + 4c
4c = 8 + -8 + 4c

Combine like terms: 8 + -8 = 0
4c = 0 + 4c
4c = 4c

Add '-4c' to each side of the equation.
4c + -4c = 4c + -4c

Combine like terms: 4c + -4c = 0
0 = 4c + -4c

Combine like terms: 4c + -4c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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