4(c+2)-2=2(c+4)

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Solution for 4(c+2)-2=2(c+4) equation: 



4(c+2)-2=2(c+4)

We move all terms to the left:

4(c+2)-2-(2(c+4))=0

We multiply parentheses

4c-(2(c+4))+8-2=0



We calculate terms in parentheses: -(2(c+4)), so:

2(c+4)

We multiply parentheses

2c+8

Back to the equation:

-(2c+8)



We add all the numbers together, and all the variables

4c-(2c+8)+6=0

We get rid of parentheses

4c-2c-8+6=0

We add all the numbers together, and all the variables

2c-2=0

We move all terms containing c to the left, all other terms to the right

2c=2

c=2/2

c=1

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