4(c+1)=5(c+1)

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Solution for 4(c+1)=5(c+1) equation:


Simplifying
4(c + 1) = 5(c + 1)

Reorder the terms:
4(1 + c) = 5(c + 1)
(1 * 4 + c * 4) = 5(c + 1)
(4 + 4c) = 5(c + 1)

Reorder the terms:
4 + 4c = 5(1 + c)
4 + 4c = (1 * 5 + c * 5)
4 + 4c = (5 + 5c)

Solving
4 + 4c = 5 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
4 + 4c + -5c = 5 + 5c + -5c

Combine like terms: 4c + -5c = -1c
4 + -1c = 5 + 5c + -5c

Combine like terms: 5c + -5c = 0
4 + -1c = 5 + 0
4 + -1c = 5

Add '-4' to each side of the equation.
4 + -4 + -1c = 5 + -4

Combine like terms: 4 + -4 = 0
0 + -1c = 5 + -4
-1c = 5 + -4

Combine like terms: 5 + -4 = 1
-1c = 1

Divide each side by '-1'.
c = -1

Simplifying
c = -1

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