4(c+1)+3=20+4c

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Solution for 4(c+1)+3=20+4c equation: 



4(c+1)+3=20+4c

We move all terms to the left:

4(c+1)+3-(20+4c)=0

We add all the numbers together, and all the variables

4(c+1)-(4c+20)+3=0

We multiply parentheses

4c-(4c+20)+4+3=0

We get rid of parentheses

4c-4c-20+4+3=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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