4(c+1)+2=1

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Solution for 4(c+1)+2=1 equation: 



4(c+1)+2=1

We move all terms to the left:

4(c+1)+2-(1)=0

We add all the numbers together, and all the variables

4(c+1)+1=0

We multiply parentheses

4c+4+1=0

We add all the numbers together, and all the variables

4c+5=0

We move all terms containing c to the left, all other terms to the right

4c=-5

c=-5/4

c=-1+1/4

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