4(b-7)=2(b+3)

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Solution for 4(b-7)=2(b+3) equation: 



4(b-7)=2(b+3)

We move all terms to the left:

4(b-7)-(2(b+3))=0

We multiply parentheses

4b-(2(b+3))-28=0



We calculate terms in parentheses: -(2(b+3)), so:

2(b+3)

We multiply parentheses

2b+6

Back to the equation:

-(2b+6)



We get rid of parentheses

4b-2b-6-28=0

We add all the numbers together, and all the variables

2b-34=0

We move all terms containing b to the left, all other terms to the right

2b=34

b=34/2

b=17

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