4(b-6)=5(b+3)

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Solution for 4(b-6)=5(b+3) equation: 



4(b-6)=5(b+3)

We move all terms to the left:

4(b-6)-(5(b+3))=0

We multiply parentheses

4b-(5(b+3))-24=0



We calculate terms in parentheses: -(5(b+3)), so:

5(b+3)

We multiply parentheses

5b+15

Back to the equation:

-(5b+15)



We get rid of parentheses

4b-5b-15-24=0

We add all the numbers together, and all the variables

-1b-39=0

We move all terms containing b to the left, all other terms to the right

-b=39

b=39/-1

b=-39

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