4(b-3)=5b-5

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Solution for 4(b-3)=5b-5 equation: 



4(b-3)=5b-5

We move all terms to the left:

4(b-3)-(5b-5)=0

We multiply parentheses

4b-(5b-5)-12=0

We get rid of parentheses

4b-5b+5-12=0

We add all the numbers together, and all the variables

-1b-7=0

We move all terms containing b to the left, all other terms to the right

-b=7

b=7/-1

b=-7

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